Resistors
Capcitors
ΣV=0 Around any closed loop
VBatt −V3 −V2 −V1=0
We know V = IR, so
VBatt
−I3R3
−I2R2
−I1R1=0
VBatt−I3R3−I2R2−I1R1=0
I is the same everywhere in a series circuit
VBatt−I(R3+R2+R1)=0
VBatt−I(R3+R2+R1)=0
In series circuits, then… VBatt−IRTotal=0
RTotal=R1+R2+R3+…
Choose a path 1→8→7→2→1, then,
VBatt−I1R1=0
Choose a different path 1→8→6→3→1
VBatt−I2R2=0
In each branch of a parallel circuit, ΔV must be the same.
V1=V2=V3=VBatt
In a parallel circuit, the current splits at each junction. So the current leaving the battery is ITotal=I1+I2+I3
And, V=IR or I=V/R which can be substituted in.
ITotal=V1/R1+V2/R2+V3/R3
ITotal=V1/R1+V2/R2+V3/R3 But, V is same across all parallel branches, so
V/RTotal=V/R1+V/R2+V/R3 V/RTotal=V(1/R1+1/R2+1/R3)
In Parallel branches 1/RTotal=1/R1+1/R2+1/R3+…
Series Circuits Current is same at all points ΣΔV=0 RTotal=R1+R2+R3+…
Parallel Circuits Voltage is same across all branches ITotal=I1+I2+I3 1/RTotal=1/R1+1/R2+1/R3+…
As capacitor charges, charge builds up on plates of capacitor, creating electric field, building up a potential difference across the capacitor.
Charging Capacitor
Charge on capacitor: Q=VC
Capacitance: C=ϵ(A/d)
Loop rule still applies, so
VBatt −VCap −VRes=0
VBatt−VCap−VRes=0
VBatt−Q/C−IR=0
VBatt−Q(t)/C−dQ(t)dtR=0
VBatt−Q(t)/C−dQ(t)dtR=0
Q(t)=Q0(1−e−t/RC)
At time = 0 Q(t)=Q0(1−e−t/RC) dQ(t)dt=Q0RCe−t/RC at t = 0, Q(0)=Q0, and I0=Q0RC=V/R
As time goes to infinity Q(t)=Q0(1−e−t/RC) dQ(t)dt=Q0RCe−t/RC as t→∞,Q(∞)=VC, and I(∞)=I0(1−1)=0
Loop rule still applies, so
VCap −VRes=0
VCap−VRes=0
Q/C−IR=0
Q(t)/C−dQ(t)dtR=0
Q(t)/C−dQ(t)dtR=0
Q(t)=VCe−t/RC
At time = 0 Q(t)=VCe−t/RC dQ(t)dt=VC−RCe−t/RC at t = 0, Q(0)=VC, and I0=−VCRC=−VC/R
As time goes to infinity Q(t)=VCe−t/RC dQ(t)dt=VC−RCe−t/RC as t→∞,Q(∞)=0, and I(∞)=VC/R=0